Aggregate two options

[siroky]

• Some(x), Some(y), f => Some(f(x, y))
• Some(x), None, f => Some(x)
• ...
• None, None, f => None

[KaliCZ]

Doesn't this result in inconsistent result type?
Assuming that f(x, y) return z, you'd need to either return a coproduct of 3 or 4 types

• Some z
• Some x
• Some y
• None z (Can be same as first if it would still be an option)

Or you'd need to accept 3 different functions resulting in z

• one taking x and y
• one taking x
• one taking y

Alternatively you would accept a function accepting option of y and option of x as parameters. In which case this method does exactly nothing, because you need to pass the two options and a function, so you might as well just call the function.

[siroky]

This will be for options of same type and the function will also return same type.

[siroky]

Duplicates #73