数字反转INT_MAXandINT_MIN的运用.cpp

class Solution {
public:
    int reverse(int x) {
        int res = 0;
        while (x != 0) {
            int mid = x % 10;
            if (res > INT_MAX / 10 || res < INT_MIN / 10) return 0;
            res = res * 10 + mid;
            x /= 10;
        }
        return res;
    }
};