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solution.py
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assignments = []
def cross(A, B):
"Cross product of elements in A and elements in B."
return [x + y for x in A for y in B]
"""
Variables for Sudoku Board
"""
rows = 'ABCDEFGHI'
cols = '123456789'
cols_rev = cols[::-1]
boxes = cross(rows, cols)
row_units = [cross(r, cols) for r in rows]
column_units = [cross(rows, c) for c in cols]
square_units = [cross(rs, cs) for rs in ('ABC','DEF','GHI') for cs in ('123','456','789')]
d1_units = [[rows[i]+cols[i] for i in range(len(rows))]]
d2_units = [[rows[i]+cols_rev[i] for i in range(len(rows))]]
unitlist = row_units + column_units + square_units + d1_units + d2_units
units = dict((s, [u for u in unitlist if s in u]) for s in boxes)
peers = dict((s, set(sum(units[s],[]))-set([s])) for s in boxes)
def assign_value(values, box, value):
"""
Please use this function to update your values dictionary!
Assigns a value to a given box. If it updates the board record it.
"""
# Don't waste memory appending actions that don't actually change any values
if values[box] == value:
return values
values[box] = value
if len(value) == 1:
assignments.append(values.copy())
return values
def naked_twins(values):
"""Eliminate values using the naked twins strategy.
Args:
values(dict): a dictionary of the form {'box_name': '123456789', ...}
Returns:
the values dictionary with the naked twins eliminated from peers.
"""
# Find all instances of naked twins
candidate_twins = [box for box in values.keys() if len(values[box]) == 2]
twins = [[box1, box2] for box1 in candidate_twins for box2 in peers[box1] if set(values[box1]) == set(values[box2])]
# Eliminate the naked twins as possibilities for their peers
for twin in twins:
box1 = twin[0]
box2 = twin[1]
peers1 = set(peers[box1])
peers2 = set(peers[box2])
common_peers = peers1 & peers2
for single_peer in common_peers:
if len(values[single_peer]) > 1:
for discard_value in values[box1]:
values = assign_value(values, single_peer, values[single_peer].replace(discard_value,''))
return values
def grid_values(grid):
"""
Convert grid into a dict of {square: char} with '123456789' for empties.
Args:
grid(string) - A grid in string form.
Returns:
A grid in dictionary form
Keys: The boxes, e.g., 'A1'
Values: The value in each box, e.g., '8'. If the box has no value, then the value will be '123456789'.
"""
values = []
default_value = '123456789'
for i in grid:
if i == ".":
values.append(default_value)
elif i in default_value:
values.append(i)
assert len(values) == 81
return dict(zip(boxes, values))
def display(values):
"""
Display the values as a 2-D grid.
Args:
values(dict): The sudoku in dictionary form
"""
width = 1+max(len(values[s]) for s in boxes)
line = '+'.join(['-'*(width*3)]*3)
for r in rows:
print(''.join(values[r+c].center(width)+('|' if c in '36' else '')
for c in cols))
if r in 'CF': print(line)
return
def eliminate(values):
"""
Goes through all the boxes, and whenever there is a box with a value, eliminates that value from the values of all its peers.
:param values: The sudoku in dictionary form
:return: The resulting sudoku in dictionary form.
"""
solved_values = [box for box in values.keys() if len(values[box]) == 1]
for box in solved_values:
digit = values[box]
for peer in peers[box]:
values[peer] = values[peer].replace(digit,'')
return values
def only_choice(values):
"""
Goes through all the units, and whenever there is a unit with a value that only fits in one box, assigns the value to that box.
:param values: The sudoku in dictionary form
:return: The resulting sudoku in dictionary form.
"""
for unit in unitlist:
for digit in '123456789':
dplaces = [box for box in unit if digit in values[box]]
if len(dplaces) == 1:
values = assign_value(values, dplaces[0], digit)
return values
def reduce_puzzle(values):
solved_values = [box for box in values.keys() if len(values[box]) == 1]
stalled = False
while not stalled:
solved_values_before = len([box for box in values.keys() if len(values[box]) == 1])
values = eliminate(values)
values = only_choice(values)
values = naked_twins(values)
solved_values_after = len([box for box in values.keys() if len(values[box]) == 1])
stalled = solved_values_before == solved_values_after
if len([box for box in values.keys() if len(values[box]) == 0]):
return False
return values
def search(values):
"Uses depth-first search and propagation, creates a search tree and solves the sudoku."
# First, reduces the puzzle using the previous function
values = reduce_puzzle(values)
if values is False:
return False ## Failed earlier
if all(len(values[s]) == 1 for s in boxes):
return values ## Solved!
# Chooses one of the unfilled squares with the fewest possibilities
n, s = min((len(values[s]), s) for s in boxes if len(values[s]) > 1)
# Uses recursion to solve each one of the resulting sudokus, and if one returns a value (not False), returns the answer!
for value in values[s]:
new_sudoku = values.copy()
new_sudoku[s] = value
attempt = search(new_sudoku)
if attempt:
return attempt
def solve(grid):
"""
Find the solution to a Sudoku grid.
Args:
grid(string): a string representing a sudoku grid.
Example: '2.............62....1....7...6..8...3...9...7...6..4...4....8....52.............3'
Returns:
The dictionary representation of the final sudoku grid. False if no solution exists.
"""
values = grid_values(grid)
values = search(values)
return values
if __name__ == '__main__':
diag_sudoku_grid = '2.............62....1....7...6..8...3...9...7...6..4...4....8....52.............3'
display(solve(diag_sudoku_grid))
try:
from visualize import visualize_assignments
visualize_assignments(assignments)
except SystemExit:
pass
except:
print('We could not visualize your board due to a pygame issue. Not a problem! It is not a requirement.')