Week2-Assessment.py

##Complete the function by filling in the missing parts. The color_translator
# function receives the name of a color, then prints its hexadecimal value. Currently,
# it only supports the three additive primary colors (red, green, blue), so it returns "unknown" for all other colors.
def color_translator(color):
	if color == "red":
		hex_color = "#ff0000"
	elif color == "green":
		hex_color = "#00ff00"
	elif color == "blue":
		hex_color = "#0000ff"
	else:
		hex_color = "unknown"
	return hex_color

print(color_translator("blue")) # Should be #0000ff
print(color_translator("yellow")) # Should be unknown
print(color_translator("red")) # Should be #ff0000
print(color_translator("black")) # Should be unknown
print(color_translator("green")) # Should be #00ff00
print(color_translator("")) # Should be unknown

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def format_name(first_name, last_name):
	if len(first_name)>0 and len(last_name)>0:
		string="Name: " +last_name+","+first_name
	elif len(first_name)==0 and len(last_name)>0:
		string="Name: "+last_name
	elif len(first_name)>0 and len(last_name)==0:
		string="Name: "+first_name
	else:
		string=""
	return string

print(format_name("Ernest", "Hemingway"))
# Should return the string "Name: Hemingway, Ernest"

print(format_name("", "Madonna"))
# Should return the string "Name: Madonna"

print(format_name("Voltaire", ""))
# Should return the string "Name: Voltaire"

print(format_name("", ""))
# Should return an empty string

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##The longest_word function is used to compare 3 words. It should return the word with the most
# number of characters (and the first in the list when they have the same length).
# Fill in the blank to make this happen.

def longest_word(word1, word2, word3):
	if len(word1) >= len(word2) and len(word1) >= len(word3):
		word = word1
	elif len(word2)>= len(word1) and len(word2) >= len(word3):
		word = word2
	else:
		word = word3
	return(word)

print(longest_word("chair", "couch", "table"))
print(longest_word("bed", "bath", "beyond"))
print(longest_word("laptop", "notebook", "desktop"))