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Copy path144.二叉树的前序遍历.php
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144.二叉树的前序遍历.php
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<?php
/*
* @lc app=leetcode.cn id=144 lang=php
*
* [144] 二叉树的前序遍历
*
* https://leetcode-cn.com/problems/binary-tree-preorder-traversal/description/
*
* algorithms
* Easy (69.83%)
* Likes: 578
* Dislikes: 0
* Total Accepted: 336.6K
* Total Submissions: 482K
* Testcase Example: '[1,null,2,3]'
*
* 给你二叉树的根节点 root ,返回它节点值的 前序 遍历。
*
*
*
* 示例 1:
*
*
* 输入:root = [1,null,2,3]
* 输出:[1,2,3]
*
*
* 示例 2:
*
*
* 输入:root = []
* 输出:[]
*
*
* 示例 3:
*
*
* 输入:root = [1]
* 输出:[1]
*
*
* 示例 4:
*
*
* 输入:root = [1,2]
* 输出:[1,2]
*
*
* 示例 5:
*
*
* 输入:root = [1,null,2]
* 输出:[1,2]
*
*
*
*
* 提示:
*
*
* 树中节点数目在范围 [0, 100] 内
* -100
*
*
*
*
* 进阶:递归算法很简单,你可以通过迭代算法完成吗?
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* class TreeNode {
* public $val = null;
* public $left = null;
* public $right = null;
* function __construct($val = 0, $left = null, $right = null) {
* $this->val = $val;
* $this->left = $left;
* $this->right = $right;
* }
* }
*/
class Solution
{
/**
* @param TreeNode $root
* @return Integer[]
*/
public function preorderTraversal($root)
{
// $orders = [];
$orders[] = $root->val;
if ($root->left) {
$orders = array_merge($orders, $this->preorderTraversal($root->left));
}
if ($root->right) {
$orders = array_merge($orders, $this->preorderTraversal($root->right));
}
return $orders;
}
}
// @lc code=end