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Easy/Friendly Movies streamed list.sql

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+-- Question 115
+-- Write an SQL query to report the distinct titles of the kid-friendly movies streamed in June 2020.
+
+-- Return the result table in any order.
+
+-- The query result format is in the following example.
+
+
+
+-- TVProgram table:
+-- +--------------------+--------------+-------------+
+-- | program_date       | content_id   | channel     |
+-- +--------------------+--------------+-------------+
+-- | 2020-06-10 08:00   | 1            | LC-Channel  |
+-- | 2020-05-11 12:00   | 2            | LC-Channel  |
+-- | 2020-05-12 12:00   | 3            | LC-Channel  |
+-- | 2020-05-13 14:00   | 4            | Disney Ch   |
+-- | 2020-06-18 14:00   | 4            | Disney Ch   |
+-- | 2020-07-15 16:00   | 5            | Disney Ch   |
+-- +--------------------+--------------+-------------+
+
+-- Content table:
+-- +------------+----------------+---------------+---------------+
+-- | content_id | title          | Kids_content  | content_type  |
+-- +------------+----------------+---------------+---------------+
+-- | 1          | Leetcode Movie | N             | Movies        |
+-- | 2          | Alg. for Kids  | Y             | Series        |
+-- | 3          | Database Sols  | N             | Series        |
+-- | 4          | Aladdin        | Y             | Movies        |
+-- | 5          | Cinderella     | Y             | Movies        |
+-- +------------+----------------+---------------+---------------+
+
+-- Result table:
+-- +--------------+
+-- | title        |
+-- +--------------+
+-- | Aladdin      |
+-- +--------------+
+-- "Leetcode Movie" is not a content for kids.
+-- "Alg. for Kids" is not a movie.
+-- "Database Sols" is not a movie
+-- "Alladin" is a movie, content for kids and was streamed in June 2020.
+-- "Cinderella" was not streamed in June 2020.
+
+-- Solution
+select distinct title
+from
+(select content_id, title
+from content
+where kids_content = 'Y' and content_type = 'Movies') a
+join
+tvprogram using (content_id)
+where month(program_date) = 6

Easy/Group sold products by the date.sql

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+-- Question 116
+-- Table Activities:
+
+-- +-------------+---------+
+-- | Column Name | Type    |
+-- +-------------+---------+
+-- | sell_date   | date    |
+-- | product     | varchar |
+-- +-------------+---------+
+-- There is no primary key for this table, it may contains duplicates.
+-- Each row of this table contains the product name and the date it was sold in a market.
+
+
+-- Write an SQL query to find for each date, the number of distinct products sold and their names.
+
+-- The sold-products names for each date should be sorted lexicographically. 
+
+-- Return the result table ordered by sell_date.
+
+-- The query result format is in the following example.
+
+-- Activities table:
+-- +------------+-------------+
+-- | sell_date  | product     |
+-- +------------+-------------+
+-- | 2020-05-30 | Headphone   |
+-- | 2020-06-01 | Pencil      |
+-- | 2020-06-02 | Mask        |
+-- | 2020-05-30 | Basketball  |
+-- | 2020-06-01 | Bible       |
+-- | 2020-06-02 | Mask        |
+-- | 2020-05-30 | T-Shirt     |
+-- +------------+-------------+
+
+-- Result table:
+-- +------------+----------+------------------------------+
+-- | sell_date  | num_sold | products                     |
+-- +------------+----------+------------------------------+
+-- | 2020-05-30 | 3        | Basketball,Headphone,T-shirt |
+-- | 2020-06-01 | 2        | Bible,Pencil                 |
+-- | 2020-06-02 | 1        | Mask                         |
+-- +------------+----------+------------------------------+
+-- For 2020-05-30, Sold items were (Headphone, Basketball, T-shirt), we sort them lexicographically and separate them by comma.
+-- For 2020-06-01, Sold items were (Pencil, Bible), we sort them lexicographically and separate them by comma.
+-- For 2020-06-02, Sold item is (Mask), we just return it.
+
+-- Solution
+select sell_date, count(distinct product) as num_sold, group_concat(distinct product) as products
+from activities
+group by 1
+order by 1