start challenge 02

02/README.md

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+## Code Challenge 02 - Word Values Part II - a simple game
+
+> This week, each one of you has a homework assignment ... - Tyler Durden (Fight club)
+
+### Given a random set of 7 letters build the most valuable word 
+
+Building upon the [last challenge](http://pybit.es/codechallenge01.html) this week part II: a simple game.
+
+### Requirements / steps
+
+* this will be a console game. Import SCRABBLE_POUCH from data.py to get the complete pool of letters
+
+* draw 7 random letters from SCRABBLE_POUCH (see [Scrabble rules](http://www.scrabblepages.com/scrabble/rules/), this will be a lite version, no board and no bonus points, keeping it simple).
+
+* ask the user to form a word with the 7 letters. 
+	* check that only letters of the draw are used. 
+	* check if a valid word, for that import the DICTIONARY set from data.py (I provided a set for O(1) lookup)
+
+* now the checker side: get all permutations for the 7 letter draw (hint: [itertools.permutations](http://pybit.es/itertools-examples.html))
+
+* cross check the collection built in last step with the dictionary to filter out valid words only.
+
+* calculate the word values of each of the remaining words, you can use code from [last challenge](http://pybit.es/codechallenge01.html) here. Import LETTER_VALUES from data.py to use in your calculations.
+
+* present the user with the highest vs the one he/she created and calculate a simple score (user word value / max word value).
+	* optional variation: give the user n attempts (defined as a constant NUM_ATTEMPTS) and feedback each time how far he/she is off from the max score.
+
+### Bonus
+
+This might be quite a challenge, but it is also a highly addictive one I think. If you want to get creative you can further build this out:
+
+* keep scores in a shelve (or sqlite3 db) and feedback each game if user reached a new max score.
+
+* work with hints (penalizing end score).
+
+* convert this in a pygame / web app. / Android app
+
+### Possible console output 
+
+### Good luck!
+
+We can't wait for your inputs! 
+
+Remember: there is no best solution, only learning and getting better Pythonistas.
+
+And above all: have fun!! 
+
+---
+
+* [Corresponding blog post](http://pybit.es/codechallenge02.html)
+
+* [Fork this project and start coding](https://github.com/pybites/challenges)
+
+### About PyBites Code Challenges
+
+Background in [our intro post](http://pybit.es/codechallenge01.html).

02/data.py

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+from collections import namedtuple
+
+Letter = namedtuple('Letter', 'name amount value')
+
+# generated with https://github.com/pybites/blog_code/blob/master/BeautifulSoup/scrabble_distribution.py
+distribution = [Letter(name='A', amount='9', value='1'), Letter(name='B', amount='2', value='3'), Letter(name='C', amount='2', value='3'), Letter(name='D', amount='4', value='2'), Letter(name='E', amount='12', value='1'), Letter(name='F', amount='2', value='4'), Letter(name='G', amount='3', value='2'), Letter(name='H', amount='2', value='4'), Letter(name='I', amount='9', value='1'), Letter(name='J', amount='1', value='8'), Letter(name='K', amount='1', value='5'), Letter(name='L', amount='4', value='1'), Letter(name='M', amount='2', value='3'), Letter(name='N', amount='6', value='1'), Letter(name='O', amount='8', value='1'), Letter(name='P', amount='2', value='3'), Letter(name='Q', amount='1', value='10'), Letter(name='R', amount='6', value='1'), Letter(name='S', amount='4', value='1'), Letter(name='T', amount='6', value='1'), Letter(name='U', amount='4', value='1'), Letter(name='V', amount='2', value='4'), Letter(name='W', amount='2', value='4'), Letter(name='X', amount='1', value='8'), Letter(name='Y', amount='2', value='4'), Letter(name='Z', amount='1', value='10')]
+
+POUNCH = list(''.join(
+        list(letter.name * int(letter.amount) 
+            for letter in distribution))
+    )
+assert len(POUNCH) == 98  # no wildcards in this simple game
+
+LETTER_VALUES = dict(zip(
+        [letter.name for letter in distribution],
+        [int(letter.value) for letter in distribution]
+    ))
+
+assert LETTER_VALUES['A'] == 1
+assert LETTER_VALUES['Q'] == 10
+assert sum(LETTER_VALUES.values()) == 87
+
+def _load_words():
+    with open('dictionary.txt') as f:
+        return set([word.strip() for word in f.read().split()])
+
+DICTIONARY = _load_words()