have to spell POUCH correctly

02/README.md

@@ -2,41 +2,75 @@
 
 > This week, each one of you has a homework assignment ... - Tyler Durden (Fight club)
 
-### Given a random set of 7 letters build the most valuable word 
+### Given a random set of 7 letters build the most valuable word 
 
-Building upon the [last challenge](http://pybit.es/codechallenge01.html) this week part II: a simple game.
+Using what we've learned [the last challenge](http://pybit.es/codechallenge01.html) this week we build a simple game.
 
 ### Requirements / steps
 
 * this will be a console game. Import SCRABBLE_POUCH from data.py to get the complete pool of letters
 
 * draw 7 random letters from SCRABBLE_POUCH (see [Scrabble rules](http://www.scrabblepages.com/scrabble/rules/), this will be a lite version, no board and no bonus points, keeping it simple).
 
+['A', 'A', 'A', 'A', 'A', 'A', 'A', 'A', 'A', 'B', 'B', 'C', 'C', 'D', 'D', 'D', 'D', 'E', 'E', 'E', 'E', 'E', 'E', 'E', 'E', 'E', 'E', 'E', 'E', 'F', 'F', 'G', 'G', 'G', 'H', 'H', 'I', 'I', 'I', 'I', 'I', 'I', 'I', 'I', 'I', 'J', 'K', 'L', 'L', 'L', 'L', 'M', 'M', 'N', 'N', 'N', 'N', 'N', 'N', 'O', 'O', 'O', 'O', 'O', 'O', 'O', 'O', 'P', 'P', 'Q', 'R', 'R', 'R', 'R', 'R', 'R', 'S', 'S', 'S', 'S', 'T', 'T', 'T', 'T', 'T', 'T', 'U', 'U', 'U', 'U', 'V', 'V', 'W', 'W', 'X', 'Y', 'Y', 'Z']
+
 * ask the user to form a word with the 7 letters. 
-	* check that only letters of the draw are used. 
-	* check if a valid word, for that import the DICTIONARY set from data.py (I provided a set for O(1) lookup)
+        * check that only letters of the draw are used. 
+        * check if a valid word, for that import the DICTIONARY set from data.py (I provided a set for O(1) lookup)
+
+Stop basic
+Print score
 
-* now the checker side: get all permutations for the 7 letter draw (hint: [itertools.permutations](http://pybit.es/itertools-examples.html))
+## Advanced: give a score based on optimal (computer calculated) solution
+
+* now the computer side: get all permutations for the 7 letter draw (hint: [itertools.permutations](http://pybit.es/itertools-examples.html))
 
 * cross check the collection built in last step with the dictionary to filter out valid words only.
 
 * calculate the word values of each of the remaining words, you can use code from [last challenge](http://pybit.es/codechallenge01.html) here. Import LETTER_VALUES from data.py to use in your calculations.
 
+
+
+# re-use from challenge 01
+def calc_word_value(word):
+    """Calc a given word value based on Scrabble LETTER_SCORES mapping"""
+    return sum(LETTER_SCORES.get(char.upper(), 0) for char in word)
+
+
+# re-use from challenge 01
+def max_word_value(words):
+    """Calc the max value of a collection of words"""
+    return max(words, key=lambda w: calc_word_value(w))
+
+
+
+
 * present the user with the highest vs the one he/she created and calculate a simple score (user word value / max word value).
-	* optional variation: give the user n attempts (defined as a constant NUM_ATTEMPTS) and feedback each time how far he/she is off from the max score.
+        * optional variation: give the user n attempts (defined as a constant NUM_ATTEMPTS) and feedback each time how far he/she is off from the max score.
+
 
-### Bonus
+
+
+### Bonus (not required)
 
 This might be quite a challenge, but it is also a highly addictive one I think. If you want to get creative you can further build this out:
 
 * keep scores in a shelve (or sqlite3 db) and feedback each game if user reached a new max score.
 
-* work with hints (penalizing end score).
+* work with hints: show some chars of the optimal word (e.g. g____y) - substract some points for using the hint
 
-* convert this in a pygame / web app. / Android app
+* give 20 extra points if all letters are used
+
+* convert this in a pygame / web app. / Android app 
 
 ### Possible console output 
 
+Letters drawn: G, A, R, Y, T, E, V
+Form a valid word: gary
+Word chosen: GARY with value: 8
+Max word: garvey with value: 13
+You scored: 61.53846153846154
+
 ### Good luck!
 
 We can't wait for your inputs! 
@@ -51,6 +85,6 @@ And above all: have fun!!
 
 * [Fork this project and start coding](https://github.com/pybites/challenges)
 
-### About PyBites Code Challenges
+### About PyBites Code Challenges
 
 Background in [our intro post](http://pybit.es/codechallenge01.html).

02/data.py

@@ -13,11 +13,11 @@ def _load_words():
 # generated with https://github.com/pybites/blog_code/blob/master/BeautifulSoup/scrabble_distribution.py
 distribution = [Letter(name='A', amount='9', value='1'), Letter(name='B', amount='2', value='3'), Letter(name='C', amount='2', value='3'), Letter(name='D', amount='4', value='2'), Letter(name='E', amount='12', value='1'), Letter(name='F', amount='2', value='4'), Letter(name='G', amount='3', value='2'), Letter(name='H', amount='2', value='4'), Letter(name='I', amount='9', value='1'), Letter(name='J', amount='1', value='8'), Letter(name='K', amount='1', value='5'), Letter(name='L', amount='4', value='1'), Letter(name='M', amount='2', value='3'), Letter(name='N', amount='6', value='1'), Letter(name='O', amount='8', value='1'), Letter(name='P', amount='2', value='3'), Letter(name='Q', amount='1', value='10'), Letter(name='R', amount='6', value='1'), Letter(name='S', amount='4', value='1'), Letter(name='T', amount='6', value='1'), Letter(name='U', amount='4', value='1'), Letter(name='V', amount='2', value='4'), Letter(name='W', amount='2', value='4'), Letter(name='X', amount='1', value='8'), Letter(name='Y', amount='2', value='4'), Letter(name='Z', amount='1', value='10')]
 
-POUNCH = list(''.join(
+POUCH = list(''.join(
         list(letter.name * int(letter.amount) 
             for letter in distribution))
     )
-assert len(POUNCH) == 98  # no wildcards in this simple game
+assert len(POUCH) == 98  # no wildcards in this simple game
 
 
 LETTER_SCORES = dict(zip(

02/game-help.py

@@ -5,7 +5,7 @@
 import itertools
 import random
 
-from data import DICTIONARY, LETTER_SCORES, POUNCH
+from data import DICTIONARY, LETTER_SCORES, POUCH
 
 NUM_LETTERS = 7
 

02/game-nohelp.py

@@ -2,7 +2,7 @@
 # Code Challenge 02 - Word Values Part II - a simple game
 # http://pybit.es/codechallenge02.html
 
-from data import DICTIONARY, LETTER_VALUES, POUNCH
+from data import DICTIONARY, LETTER_VALUES, POUCH
 
 NUM_LETTERS = 7